14=-2.7t^2+50t+6.5

Solution for 14=-2.7t^2+50t+6.5 equation:

14=-2.7t^2+50t+6.5

We move all terms to the left:

14-(-2.7t^2+50t+6.5)=0

We get rid of parentheses

2.7t^2-50t-6.5+14=0

We add all the numbers together, and all the variables

2.7t^2-50t+7.5=0

a = 2.7; b = -50; c = +7.5;
Δ = b2-4ac
Δ = -502-4·2.7·7.5
Δ = 2419
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-\sqrt{2419}}{2*2.7}=\frac{50-\sqrt{2419}}{5.4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+\sqrt{2419}}{2*2.7}=\frac{50+\sqrt{2419}}{5.4}
$